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std.datetime.interval.NegInfInterval.shift - multiple declarations

Function NegInfInterval.shift

Shifts the end of this interval forward or backwards in time by the given duration (a positive duration shifts the interval forward; a negative duration shifts it backward). Effectively, it does end += duration.

void shift(D) (
  D duration
) pure nothrow
if (__traits(compiles, end + duration));

Parameters

NameDescription
duration The duration to shift the interval by.

Example

auto interval1 = NegInfInterval!Date(Date(2012, 4, 5));
auto interval2 = NegInfInterval!Date(Date(2012, 4, 5));

interval1.shift(dur!"days"(50));
assert(interval1 == NegInfInterval!Date(Date(2012, 5, 25)));

interval2.shift(dur!"days"(-50));
assert(interval2 == NegInfInterval!Date( Date(2012, 2, 15)));

Function NegInfInterval.shift

Shifts the end of this interval forward or backwards in time by the given number of years and/or months (a positive number of years and months shifts the interval forward; a negative number shifts it backward). It adds the years the given years and months to end. It effectively calls add!"years"() and then add!"months"() on end with the given number of years and months.

void shift(T) (
  T years,
  T months = 0,
  AllowDayOverflow allowOverflow = AllowDayOverflow.yes
)
if (isIntegral!T);

Parameters

NameDescription
years The number of years to shift the interval by.
months The number of months to shift the interval by.
allowOverflow Whether the days should be allowed to overflow on end, causing its month to increment.

Throws

DateTimeException if empty is true or if the resulting interval would be invalid.

Example

auto interval1 = NegInfInterval!Date(Date(2012, 3, 1));
auto interval2 = NegInfInterval!Date(Date(2012, 3, 1));

interval1.shift(2);
assert(interval1 == NegInfInterval!Date(Date(2014, 3, 1)));

interval2.shift(-2);
assert(interval2 == NegInfInterval!Date(Date(2010, 3, 1)));

Authors

Jonathan M Davis

License

Boost License 1.0.