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Function `std.array.overlap`

Returns the overlapping portion, if any, of two arrays. Unlike equal, overlap only compares the pointers and lengths in the ranges, not the values referred by them. If r1 and r2 have an overlapping slice, returns that slice. Otherwise, returns the null slice.


						
				CommonType!(T[],U[]) overlap(T, U)(
				
  T[] a,
				
  U[] b
				

				) @trusted
				

				if (is(typeof(a.ptr < b.ptr) == bool));

Parameters

Name	Description
a	The first array to compare
b	The second array to compare

Returns

The overlapping portion of the two arrays.

Example

int[] a = [ 10, 11, 12, 13, 14 ];
int[] b = a[1 .. 3];
writeln(overlap(a, b)); // [11, 12]
b = b.dup;
// overlap disappears even though the content is the same
assert(overlap(a, b).empty);

static test()() @nogc
{
    auto a = "It's three o'clock"d;
    auto b = a[5 .. 10];
    return b.overlap(a);
}

//works at compile-time
static assert(test == "three"d);

Authors

Andrei Alexandrescu and Jonathan M Davis

License

Boost License 1.0.