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Function std.datetime.interval.everyDayOfWeek

Range-generating function.

TP delegate(scope const TP) everyDayOfWeek(TP, Direction dir = Direction.fwd) (
  DayOfWeek dayOfWeek
) nothrow
if (isTimePoint!TP && (dir == Direction.fwd || dir == Direction.bwd) && __traits(hasMember, TP, "dayOfWeek") && !__traits(isStaticFunction, TP.dayOfWeek) && is(typeof(TP.dayOfWeek) == DayOfWeek));

Returns a delegate which returns the next time point with the given DayOfWeek in a range.

Using this delegate allows iteration over successive time points which are all the same day of the week. e.g. passing DayOfWeek.mon to everyDayOfWeek would result in a delegate which could be used to iterate over all of the Mondays in a range.

Parameters

NameDescription
dir The direction to iterate in. If passing the return value to fwdRange, use Direction.fwd. If passing it to bwdRange, use Direction.bwd.
dayOfWeek The week that each time point in the range will be.

Example

import std.datetime.date : Date, DayOfWeek;

auto interval = Interval!Date(Date(2010, 9, 2), Date(2010, 9, 27));
auto func = everyDayOfWeek!Date(DayOfWeek.mon);
auto range = interval.fwdRange(func);

// A Thursday. Using PopFirst.yes would have made this Date(2010, 9, 6).
writeln(range.front); // Date(2010, 9, 2)

range.popFront();
writeln(range.front); // Date(2010, 9, 6)

range.popFront();
writeln(range.front); // Date(2010, 9, 13)

range.popFront();
writeln(range.front); // Date(2010, 9, 20)

range.popFront();
assert(range.empty);

Authors

Jonathan M Davis

License

Boost License 1.0.