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Template std.algorithm.iteration.each

Eagerly iterates over r and calls fun with each element.

template each(alias fun) ;

If no function to call is specified, each defaults to doing nothing but consuming the entire range. r.front will be evaluated, but that can be avoided by specifying a lambda with a lazy parameter.

each also supports opApply-based types, so it works with e.g. parallel.

Normally the entire range is iterated. If partial iteration (early stopping) is desired, fun needs to return a value of type Flag!"each" (Yes.each to continue iteration, or No.each to stop iteration).

Contained Functions



fun function to apply to each element of the range
r range or iterable over which each iterates


Yes.each if the entire range was iterated, No.each in case of early stopping.

See Also



import std.range : iota;
import std.typecons : No;

int[] arr;
iota(5).each!(n => arr ~= n);
writeln(arr); // [0, 1, 2, 3, 4]

// stop iterating early
iota(5).each!((n) { arr ~= n; return No.each; });
writeln(arr); // [0, 1, 2, 3, 4, 0]

// If the range supports it, the value can be mutated in place
arr.each!((ref n) => n++);
writeln(arr); // [1, 2, 3, 4, 5, 1]

writeln(arr); // [2, 3, 4, 5, 6, 2]

auto m =!(n => n);
// by-ref lambdas are not allowed for non-ref ranges
static assert(!__traits(compiles, m.each!((ref n) => n++)));

// The default predicate consumes the range


each can pass an index variable for iterable objects which support this

auto arr = new size_t[4];

writeln(arr); // [0, 1, 2, 3]

arr.each!((i, ref e) => e = i * 2);
writeln(arr); // [0, 2, 4, 6]


opApply iterators work as well

static class S
    int x;
    int opApply(scope int delegate(ref int _x) dg) { return dg(x); }

auto s = new S;
writeln(s.x); // 1


Andrei Alexandrescu


Boost License 1.0.